Chapter 3: Work, Energy, Power & System of Particles (Set-4)

Net work done on a body is equal to:

A Change in potential energy
B Change in kinetic energy
C Change in mass
D Change in force

A force acts at an angle of 90°. Work done is:

A Maximum
B Minimum positive
C Negative
D Zero

If a body gains 30 J of KE, then work done is:

A 0 J
B 15 J
C 30 J
D 60 J

For work to be done, displacement must be:

A Zero
B Along direction of force
C Opposite direction only
D Always downward

If work done is negative, the body:

A Speeds up
B Slows down
C Moves in circle
D Has constant KE

A force of 10 N causes 4 m displacement at 30°. Work =

A 20 J
B 25 J
C 34 J
D 40 J

KE of mass 1 kg moving at 6 m/s is:

A 18 J
B 36 J
C 12 J
D 6 J

Work = 40 J, displacement = 5 m. Force =

A 5 N
B 6 N
C 8 N
D 10 N

If force triples and displacement doubles, work becomes:

A
B
C
D

Work done by constant force is:

A Dot product of F and d
B Cross product of F and d
C Sum of F and d
D Independent of angle

In a closed path, work done by gravity is:

A Positive
B Negative
C Zero
D Maximum

Friction reduces:

A Potential energy
B Mechanical energy
C Mass
D Velocity only

Path-dependent work is done by:

A Gravity
B Spring force
C Electrostatic force
D Friction

Non-conservative force example:

A Magnetic
B Friction
C Electric
D Gravitational

Potential energy is defined for:

A Friction
B Air drag
C Conservative forces
D Collisions

Spring force is:

A Non-conservative always
B Conservative
C Zero force
D Only dissipative

Energy lost to friction appears as:

A KE
B Heat
C Chemical energy
D Elastic energy

Work done by non-conservative forces equals:

A Gain in KE only
B Loss in KE only
C Change in mechanical energy
D Zero

COM of rigid body depends on:

A Velocity
B Shape + mass distribution
C Force
D Pressure

For two masses, COM lies closer to:

A Lower mass
B Higher mass
C Midpoint always
D Centre of pressure

COM of ring lies at:

A On the ring
B At centre (hollow point)
C At edge
D Outside circle

Motion of COM changes only due to:

A Internal forces
B Random forces
C External forces
D Balanced forces

For an isolated system:

A COM accelerates
B COM velocity constant
C COM disappears
D COM must be at origin

COM of projectile motion follows:

A Straight line
B Circular path
C Parabolic path
D Zig-zag path

If two masses are equal, their COM lies:

A Midway
B At heavier one
C At lighter one
D Cannot be determined

COM of system is defined as:

A Position of minimum mass
B Average of all coordinates equally
C Mass-weighted average position
D Point of highest energy

Momentum is conserved when:

A Internal forces present
B External force present
C No external force
D System accelerates

Momentum of 2 kg mass moving at 5 m/s:

A 2
B 7
C 10
D 12

Impulse is equal to:

A F/v
B Force × displacement
C Change in momentum
D KE change

In elastic collision:

A Only KE conserved
B Only momentum conserved
C No conservation
D Both conserved

Momentum is a:

A Scalar
B Vector
C Pseudo quantity
D Constant

Perfectly inelastic collision has:

A Maximum KE loss
B No KE loss
C No momentum
D Zero displacement

Rate of change of momentum gives:

A Work
B Impulse
C Force
D Energy

If impulse is 20 Ns on 4 kg mass, change in velocity =

A 3 m/s
B 4 m/s
C 5 m/s
D 6 m/s

Mechanical energy remains constant when:

A Friction acts
B Only conservative forces act
C System rotates
D Mass changes

A falling object converts:

A KE → PE
B PE → KE
C KE → heat
D PE → mass

PE is stored due to:

A Speed
B Temperature
C Position/configuration
D Pressure

KE of a body with mass m and speed v is:

A mv
B mv²
C ½mv²
D 2mv

If KE increases, work done must be:

A Zero
B Negative
C Positive
D Infinite

Falling body’s total ME remains constant when:

A Air resistance is present
B Mass changes
C No dissipative force
D KE = 0

Compressed spring energy =

A Chemical
B Nuclear
C Elastic PE
D Rotational

A 6 kg mass moving at 3 m/s has KE =

A 18 J
B 27 J
C 36 J
D 54 J

Work done by a force is zero when:

A Speed increases
B Displacement zero
C Force high
D Mass large

Momentum of system changes only when:

A Internal forces act
B Mass increases
C External force acts
D Distance increases

Area under F–x graph gives:

A Velocity
B Work
C Momentum
D Power

Power becomes maximum when:

A Force zero
B Velocity zero
C Force and velocity are maximum
D KE zero

If force is perpendicular to displacement, then:

A Work positive
B Work negative
C Work zero
D Work maximum

In explosion, COM of fragments:

A Moves randomly
B Remains at rest
C Accelerates
D Changes direction

Total energy of an isolated system:

A Increases
B Decreases
C Remains constant
D Becomes zero

If KE = 50 J and PE = 150 J, total ME =

A 50 J
B 150 J
C 200 J
D 100 J