Torque depends on:
A Force only
B Distance only
C Both force & perpendicular distance
D Mass distribution
τ = r⊥F.
Angular momentum of a system changes when:
A Internal torque acts
B No torque acts
C External torque acts
D Mass increases
Only external torque changes L.
A bicycle wheel maintains direction due to:
A Large KE
B Gravitational force
C Angular momentum
D Air resistance
Gyroscopic stability.
A figure skater spins faster by:
A Extending arms
B Pulling arms in
C Stopping rotation
D Increasing friction
MoI decreases → ω increases.
Angular momentum depends on:
A Position vector only
B Linear momentum only
C Both r and p
D Gravitational force
L = r × p.
If torque is doubled and MoI constant, angular acceleration:
A Halves
B Doubles
C Triples
D Zero
α = τ/I.
Angular momentum of Earth around Sun is conserved because:
A Rotation is constant
B Sun’s gravity provides central force
C Mass is fixed
D Distance doesn’t change
Central force → no torque.
Gyroscope resists tilting because of:
A Inertia
B Gravity
C Angular momentum
D Linear speed
Direction of L resists change.
Torque is zero if:
A Force is zero
B Distance = 0
C Force direction passes through pivot
D All above
All conditions → τ = 0.
Units of angular impulse:
A N·m
B kg·m/s
C N·m·s
D J
Angular impulse = τ × t.
MoI increases when:
A Speed increases
B Mass moves farther from axis
C Temperature rises
D Axis removed
I ∝ r².
A thin hoop has MoI =
A 1/2 MR²
B 1/4 MR²
C MR²
D 2/3 MR²
All mass at distance R.
The property resisting change in rotational motion is:
A Energy
B Momentum
C Moment of inertia
D Torque
Rotational analogue of mass.
MoI of a solid sphere about an axis through centre:
A 2/5 MR²
B 1/2 MR²
C MR²
D 3/4 MR²
Standard formula.
Which body accelerates fastest down incline?
A Ring
B Disc
C Hollow sphere
D Solid sphere
Smallest ratio I/MR².
Radius of gyration decreases when:
A MoI increases
B Mass concentrated near axis
C Radius increases
D Temperature decreases
k = √(I/M).
Rotational KE does NOT depend on:
A MoI
B Shape
C Angular speed
D Linear velocity
KE_rot = ½ Iω².
For same mass, MoI is smallest for:
A Rod
B Ring
C Disc
D Point mass at centre
r = 0 → I = 0.
Parallel axis theorem applies when axis is:
A Perpendicular
B Rotating
C Parallel
D Tilted
Axis must be parallel to COM axis.
Perpendicular axis theorem:
A Iₓ + Iᵧ = I_z
B Iₓ = Iᵧ + I_z
C I_z = IₓIᵧ
D I_z = 2Iₓ
Applies to planar lamina.
Rotational Newton’s law:
A F = ma
B p = mv
C τ = Iα
D L = Iω
Torque produces angular acceleration.
Unit of angular acceleration:
A m/s
B rad/s
C rad/s²
D m/s²
Rate of change of angular velocity.
Rotational equilibrium requires:
A Net force = 0
B Net torque = 0
C KE = 0
D ω = constant
No torque → no angular acceleration.
Disc and ring rolled same incline; disc reaches earlier because:
A Mass larger
B Disc smaller MoI
C Ring lighter
D Gravity more on disc
Smaller MoI → higher angular acceleration.
For pure rolling, acceleration relation:
A a = αr
B a = r/α
C a = α/r
D a = r²α
Linear acceleration = angular acceleration × radius.
If torque constant & MoI decreases, α:
A Increases
B Decreases
C Zero
D No effect
α ∝ 1/I.
Angular displacement measured in:
A Radians
B Degree per second
C m/s
D J
Fundamental unit.
A wheel rotating with constant ω has:
A Zero α
B Positive α
C Negative α
D Variable α
No change in ω.
Rolling object’s KE includes:
A Translational only
B Rotational only
C Translational + rotational
D None
Combination of both.
Angular momentum conserved in:
A All systems
B Only isolated systems
C Bodies with zero mass
D Uniform motion
Requires no external torque.
Central forces produce:
A Zero torque
B Maximum torque
C Constant torque
D Changing angular momentum
Force through centre → no lever arm.
In central force field, path is always:
A Circular
B Linear
C Planar
D Three-dimensional
Motion confined to plane.
Non-central forces produce:
A No angular change
B Angular momentum change
C Zero energy
D No effect
Torque ≠ 0.
Central force direction:
A Tangential
B Radial
C Perpendicular
D Parallel to velocity
Acts along radius.
Gravity is a:
A Non-central force
B Central force
C Tangential force
D Rotational force
Acts along centre-to-centre line.
Coulomb & gravitational force both follow:
A Linear law
B Inverse square law
C Constant law
D Quadratic law
Both ∝ 1/r².
F ∝ 1/r² implies:
A Long-range force
B Short-range force
C No conservation laws
D Constant force
Inverse square forces act over large distances.
If r → 0, gravitational force becomes:
A Zero
B Constant
C Infinite (ideal model)
D Negative
∝ 1/r² → blows up as r→0.
G is dimensionally:
A [M¹L³T⁻²]
B [M⁻¹L³T⁻²]
C [M⁻²L⁻²T²]
D [MLT]
From F = GMm/r².
The law F ∝ 1/r² suggests:
A Spherical symmetry
B Linear motion
C Variable mass
D Zero torque
Spherically symmetric fields follow inverse square law.
g decreases with:
A Height
B Depth
C Both height & depth
D Neither
Above or below surface → g reduces.
At infinite height, gravitational potential =
A Positive
B Negative
C Zero
D Maximum negative
By convention U(∞) = 0.
Orbital velocity at height h:
A √(GM/R)
B √(GM/(R+h))
C GM/(R+h)²
D √(2GM/R)
Derived from centripetal force.
Escape velocity from Earth:
A 5 km/s
B 7 km/s
C 11.2 km/s
D 15 km/s
Standard Earth escape speed.
g is maximum at:
A Equator
B Poles
C Centre
D Tropics
Due to Earth’s shape & rotation.
Total energy of satellite in circular orbit =
A KE
B PE
C −½ GMm/R
D +GMm/R
Total energy negative in bound orbit.
Work done by gravity during free fall:
A Zero
B Positive
C Negative
D Equal to KE decrease
Gravity aids motion.
A geostationary satellite stays above same point because:
A Fast orbit
B Period = 24 h
C Zero energy
D Perigee constant
Matches Earth’s rotation.
Gravitational force between two objects depends on:
A Masses & radius
B Velocity
C Temperature
D Charge
F = GMm/r².
Astronauts feel weightless because:
A No gravity
B Free fall inside spacecraft
C No mass
D Pressure low
They accelerate with spacecraft → apparent weightlessness.