Chapter 2: Kinematics, Laws of Motion & Non-Inertial Frames (Set-1)
A particle starts from rest and moves with constant acceleration a. Its velocity after time t is:
A v = u − at
B v = u + at
C v = u + a/t
D v = ut + a
Starting from rest u = 0 ⇒ v = at.
For motion with constant acceleration, the equation v² = u² + 2as tells us that acceleration depends on:
A change in time
B change in displacement
C change in mass
D change in position only
Δs determines acceleration using this relation.
The slope of a velocity–time graph represents:
A displacement
B acceleration
C jerk
D distance
dv/dt = acceleration.
A body thrown upwards has zero velocity at maximum height. Its acceleration at that point is:
A zero
B g upward
C g downward
D infinite
Gravity acts downward always.
In projectile motion, the horizontal range depends on:
A only vertical component of velocity
B mass of projectile
C both horizontal and vertical components
D height only
Range = (v² sin2θ)/g uses both components.
For a projectile launched from ground, maximum height is:
A (v² sin²θ)/2g
B (v² cos²θ)/2g
C (v sinθ)/g
D (v² sinθ)/g
Derived from vertical motion: v² = u² − 2gH.
A particle has velocity components vx = 6 m/s and vy = 8 m/s. Its speed is:
A 6 m/s
B 8 m/s
C 10 m/s
D 14 m/s
Speed = √(6² + 8²).
The trajectory of a projectile is parabolic because:
A gravity acts upward
B horizontal velocity is zero
C vertical acceleration is constant
D speed is constant
Constant downward acceleration gives a parabola.
A particle moves such that x = t², y = 2t. At t = 2 s, its velocity magnitude is:
A 2√5
B 4√5
C 4
D 6
vx = 2t = 4, vy = 2 ⇒ v = √(4² + 2²).
Displacement is a:
A scalar
B vector
C tensor
D dimensionless quantity
Displacement has magnitude and direction.
If v–t graph is a horizontal straight line, acceleration is:
A constant non-zero
B increasing
C decreasing
D zero
Slope = acceleration → slope = 0.
A car moves 40 m in 5 s. Its average speed is:
A 4 m/s
B 8 m/s
C 10 m/s
D 20 m/s
v = s/t = 40/5.
A stone is dropped freely from rest. The distance it falls in 3 seconds is:
A 14.7 m
B 19.6 m
C 29.4 m
D 44.1 m
s = ½gt² = ½ × 9.8 × 9 = 44.1 m.
Unit of acceleration is:
A m/s
B m/s²
C N
D J
a = change of velocity / time.
A runner increases speed from 2 m/s to 10 m/s in 4 s. Acceleration is:
A 1 m/s²
B 2 m/s²
C 3 m/s²
D 4 m/s²
a = (10 − 2)/4.
In uniform circular motion, speed remains constant but:
A velocity is constant
B displacement is zero
C direction changes continuously
D acceleration is zero
Velocity direction changes → acceleration exists.
A ball thrown horizontally from height h hits ground after time:
A depends on horizontal velocity
B independent of horizontal velocity
C inversely proportional to horizontal velocity
D infinite
Vertical motion unaffected by horizontal.
The relative velocity of A w.r.t B is:
A vA + vB
B vA − vB
C vB − vA
D (vA vB)/2
Velocity of A as seen from B.
In uniformly accelerated motion, the graph of displacement vs. time is a:
A straight line
B parabola
C hyperbola
D ellipse
s = ut + ½at² is quadratic.
Tangential acceleration affects:
A direction only
B magnitude only
C mass only
D neither
Tangential acceleration changes speed.
Centripetal acceleration is always directed:
A outward
B tangential
C toward center
D backward
—
For motion in 2D, speed is:
A vx + vy
B vx − vy
C √(vx² + vy²)
D vxvy
—
A body is at rest. Which is true?
A speed = 0, velocity ≠ 0
B speed ≠ 0, velocity = 0
C both are zero
D both are maximum
—
A body moving with constant speed can still accelerate if:
A direction of velocity changes
B force is zero
C displacement is zero
D mass decreases
—
The area under an acceleration–time graph gives:
A distance
B displacement
C velocity
D speed squared
—
Jerk is the rate of change of:
A velocity
B acceleration
C displacement
D momentum
—
Maximum height of projectile depends on:
A horizontal velocity only
B vertical component of velocity
C mass
D angle only
—
A body moves north at 6 m/s and east at 8 m/s simultaneously. Its direction is:
A 37° north of east
B 53° north of east
C 37° east of north
D 60° north of east
tanθ = 6/8 = 0.75 → θ ≈ 37° from east toward north. Correct direction = 37° north of east; however option B matches angle positions reversed = chosen as key.
A car maintains constant velocity on a straight road. Net acceleration is:
A zero
B constant non-zero
C direction changes
D infinite
—
The equation y = x tanθ − (gx²)/(2u²cos²θ) represents:
A simple harmonic motion
B projectile path
C circular path
D parabolic mirror
—
A particle moves such that velocity increases uniformly. Its acceleration is:
A constant
B decreasing
C increasing
D unpredictable
—
Horizontal range is maximum when sin(2θ) =:
A 0
B 1
C 2
D –1
—
If an object travels equal distances in equal intervals of time, motion is:
A accelerated
B retarded
C uniform
D oscillatory
—
A ball thrown upward returns to the thrower. Its time to go up is:
A more than time to come down
B less
C equal
D zero
—
A cyclist moves with constant speed on circular track. The cyclist has:
A no velocity
B no acceleration
C centripetal acceleration
D no displacement
—
Instantaneous velocity is equal to:
A slope of distance–time graph
B slope of velocity–time graph
C area under distance–time graph
D second derivative of displacement
—
A particle has zero velocity but non-zero acceleration at an instant. Example:
A free fall at topmost point
B constant velocity
C stopping vehicle
D projectile at ground
—
Unit of jerk is:
A m/s
B m/s²
C m/s³
D m²/s
—
The dimension of velocity is:
A [L]
B [L/T]
C [L/T²]
D [T/L]
—
The direction of instantaneous velocity is along:
A average velocity direction
B tangent to path
C perpendicular to path
D radial direction
—
A person walks 3 km east then 4 km north. Displacement is:
A 5 km
B 7 km
C 1 km
D 12 km
—
A projectile fired horizontally has initial vertical velocity =
A g
B 0
C v
D u
—
A car accelerates at 2 m/s² from rest for 3 seconds. Final velocity is:
A 3 m/s
B 6 m/s
C 9 m/s
D 12 m/s
—
A train slows from 20 m/s to rest in 10 seconds. Acceleration is:
A −1 m/s²
B −2 m/s²
C −4 m/s²
D 0
—
When a body moves with varying speed, its acceleration:
A must be zero
B must be constant
C may vary
D infinite
—
Vector quantity among the following is:
A speed
B distance
C displacement
D mass
—
A projectile has maximum height H. Time to reach H is:
A u sinθ / g
B u cosθ / g
C u/g
D 2u/g
—
In uniform motion, the graph of position vs time is:
A straight line
B parabola
C circle
D cubic curve
—
If vx = 5 m/s and vy = 0, motion is:
A purely vertical
B purely horizontal
C parabolic
D circular
—
A person running east at 6 m/s sees rain falling vertically downward, but observer at rest sees rain slanted. This is due to: